1035. Password (20)-白红宇

1035. Password (20)

阅读量：4151 次

发布时间：2019-05-25

本文共 1272 字，大约阅读时间需要 4 分钟。

考察对应字符转化以及信息记录

#include
   
    #include
    
     #include
     
      typedef struct user{	char name[20];	char password[20];	bool modified;}User;bool IsModified(User& a){	int len = strlen(a.password);	bool ret = false;	for(int i = 0; i < len; ++i)	{		if(a.password[i] == '1')		{			a.password[i] = '@';			ret = true;		}		else if(a.password[i] == '0')		{			a.password[i] = '%';			ret = true;		}		else if(a.password[i] == 'l')		{			a.password[i] = 'L';			ret = true;		}		else if(a.password[i] == 'O')		{			a.password[i] = 'o';			ret = true;		}	}	return ret;}int main(){	int N;	while(scanf("%d", &N) != EOF)	{		std::vector
      
        userVec(N);		int modifiedCnt = 0;		for(int i = 0; i < N; ++i)		{			scanf("%s %s",userVec[i].name, userVec[i].password);						if( IsModified(userVec[i]) )			{				userVec[i].modified = true;				modifiedCnt++;			}			else userVec[i].modified = false;		}		//output		if(modifiedCnt == 0)		{			if(N <= 1)				printf("There is %d account and no account is modified\n", N);			else				printf("There are %d accounts and no account is modified\n", N);		}		else		{			printf("%d\n", modifiedCnt);			for(int i = 0; i < N; ++i)			{				if(true == userVec[i].modified)				{					printf("%s %s\n", userVec[i].name, userVec[i].password);				}			}		}	}	return 0;}